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y^2+8y-308=0
a = 1; b = 8; c = -308;
Δ = b2-4ac
Δ = 82-4·1·(-308)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-36}{2*1}=\frac{-44}{2} =-22 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+36}{2*1}=\frac{28}{2} =14 $
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